(no subject)
Jul. 6th, 2012 06:11 pmLong summer days. With children.
Mrmoosie's family is visiting, so we are having a lot of fun, but getting totally off schedule.
I spent three hours today on a practice test for chemistry. I actually did quite well, so I am feeling more confident. It was long and exhausting, however.
Not really sure how to take logarithms without a table of them or a calculator. Is this something I learned in math, or never learned? I do remember using the tables of logarithms.
Mrmoosie's family is visiting, so we are having a lot of fun, but getting totally off schedule.
I spent three hours today on a practice test for chemistry. I actually did quite well, so I am feeling more confident. It was long and exhausting, however.
Not really sure how to take logarithms without a table of them or a calculator. Is this something I learned in math, or never learned? I do remember using the tables of logarithms.
The Math Geek Says: That's not possible. There'd have to be no upper bound on the number of atoms in the hormone. In a person who weighs, say, 100 kg, there are no more than 6.022*1028 atoms (that's the number if they were all hydrogen atoms); and there can't be more atoms in the hormone than there are in the entire body.
Now, granted, the only upper bound I can place on the number of hormones (without knowing more about their structure) is (6.022*1028)!, which certainly qualifies as Lots. But it's still finite. :-)" from
metageek 's comment at least a year ago.
Possible hormones in the digestive system are peptide hormones so they are composed of any of 20 amino acids, in a chain of length 3 to 30 amino acids long. So a mathematical expression for that would be:
20^3 +20^4 +20^5 + ... + 20^30, where the ... is terms of 20^n for n=6 to 29. Is there any compact way to express this? Is there a way of doing this in a shorter way?