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Let's see here...
N = ∑3 ≤ i ≤ 30 20i
N = 202 ∑1 ≤ i ≤ 28 20i
Now, the next step involves knowing that (x-1)(xn + xn-1 + … x1 + 1) = xn+1-1. So we have:
N = 202 (2029-1)/(20-1)
...which comes out to 11,302,545,200. Not even a trillion.
Thanks!!!
How did you get the summation sign? and the subscripts/superscripts to appear?
Don't be shocked if I tell you that the top number of amino acids is actually smaller than 30. There is a top number, but I don't actually know it. So, yeah, not even a trillion. But more than I can comfortably memorize.
How did you get the summation sign? and the subscripts/superscripts to appear?
Don't be shocked if I tell you that the top number of amino acids is actually smaller than 30. There is a top number, but I don't actually know it. So, yeah, not even a trillion. But more than I can comfortably memorize.
How did you get the summation sign? and the subscripts/superscripts to appear?
Summation is just ∑ (see Character entity references in HTML 4, from the HTML spec); (sub|super)scripts are <sub> and <sup>, respectively.
The Math Geek Says: That's not possible. There'd have to be no upper bound on the number of atoms in the hormone. In a person who weighs, say, 100 kg, there are no more than 6.022*1028 atoms (that's the number if they were all hydrogen atoms); and there can't be more atoms in the hormone than there are in the entire body.
Now, granted, the only upper bound I can place on the number of hormones (without knowing more about their structure) is (6.022*1028)!, which certainly qualifies as Lots. But it's still finite. :-)" from
metageek 's comment at least a year ago.
Possible hormones in the digestive system are peptide hormones so they are composed of any of 20 amino acids, in a chain of length 3 to 30 amino acids long. So a mathematical expression for that would be:
20^3 +20^4 +20^5 + ... + 20^30, where the ... is terms of 20^n for n=6 to 29. Is there any compact way to express this? Is there a way of doing this in a shorter way?